> When I was compiling the following code, I got an error:
> cannot convert parameter 1 from 'Four' to 'Three'. but If
> I use general member function(commented code) instead of
> template function, it works well.

> Would you please tell me what is the problem? thanks.

> //------------- code --------------
> #include <string>
> #include <iostream>
> using namespace std;

> class Three {
>   int i;
> public:
>   Three(int ii = 0, int = 0) : i(ii) { }
> };

> class Four {
>   int x;
> public:
>   Four(int xx) : x( xx) { }

>   template<class T> operator T(){
>     return T(x);
>   }

>   //operator Three() const {
>   // return Three(x);
>   //}
> };

> void g(Three) { }
> int main(int argc, char* argv[])
> {
>   Four four(1) ;
>   g(four) ;

>   return 0;
> }

> -cd

> > I want to use operator overloading template function to
> > produce automatic type conversion.

> > When I was compiling the following code, I got an error:
> > cannot convert parameter 1 from 'Four' to 'Three'. but If
> > I use general member function(commented code) instead of
> > template function, it works well.

> > Would you please tell me what is the problem? thanks.

> > //------------- code --------------
> > #include <string>
> > #include <iostream>
> > using namespace std;

> > class Three {
> >   int i;
> > public:
> >   Three(int ii = 0, int = 0) : i(ii) { }
> > };

> > class Four {
> >   int x;
> > public:
> >   Four(int xx) : x( xx) { }

> >   template<class T> operator T(){
> >     return T(x);
> >   }

> >   //operator Three() const {
> >   // return Three(x);
> >   //}
> > };

> > void g(Three) { }
> > int main(int argc, char* argv[])
> > {
> >   Four four(1) ;
> >   g(four) ;

> >   return 0;
> > }

> I'm using VC 6.0. Is there a way to let it being compiled in VC 6.0?

>> What compiler are you using?  This code compiles fine with VC7.1 (as
>> it should).

>> -cd

>>> I want to use operator overloading template function to
>>> produce automatic type conversion.

>>> When I was compiling the following code, I got an error:
>>> cannot convert parameter 1 from 'Four' to 'Three'. but If
>>> I use general member function(commented code) instead of
>>> template function, it works well.

>>> Would you please tell me what is the problem? thanks.

>>> //------------- code --------------
>>> #include <string>
>>> #include <iostream>
>>> using namespace std;

>>> class Three {
>>>   int i;
>>> public:
>>>   Three(int ii = 0, int = 0) : i(ii) { }
>>> };

>>> class Four {
>>>   int x;
>>> public:
>>>   Four(int xx) : x( xx) { }

>>>   template<class T> operator T(){
>>>     return T(x);
>>>   }

>>>   //operator Three() const {
>>>   // return Three(x);
>>>   //}
>>> };

>>> void g(Three) { }
>>> int main(int argc, char* argv[])
>>> {
>>>   Four four(1) ;
>>>   g(four) ;

>>>   return 0;
>>> }