I've developed a MFC application that is dialog based (so it's not SDI or
MDI!): It's main window is a dialog. Because I've attached a tray icon to
this application and a Hide button it has the feature of hiding itself and
when double clicking on the tray icon it displays the window. When clicking
on the Hide button I just call ShowWindow(SW_HIDE). However I also want this
application to hide itself when started up. So I guessed I put the same call
into the OnInitDialog function, however that does not work.
Does anybody have a good idea to make this work. I tried SendMessage,
PostMessage (all from the OnInitDialog function), but they either don't work
or make the application end-up in an endless loop killing itself.

Regards,
Rob

I've not come across a really elegant way of doing this. The best I've
got is to post a user defined message in OnInitDialog, and position
the dialog off-screen. In the processing of the user defined message
hide the window, and when you want to display it you can reposition
it. Here's the general idea:

BEGIN_MESSAGE_MAP(CMindlgDlg, CDialog)
        //{{AFX_MSG_MAP(CMindlgDlg)
        ...
        //}}AFX_MSG_MAP
        ON_MESSAGE( WM_APP+1, OnAppMsg )
END_MESSAGE_MAP()

BOOL CMindlgDlg::OnInitDialog()
{
        ...

        // TODO: Add extra initialization here
        SetWindowPos( NULL, -1000, -1000, 0, 0,
                        SWP_NOZORDER | SWP_NOSIZE | SWP_NOACTIVATE );

        PostMessage( WM_APP+1 );

        return TRUE;

That doesn't hide it - it makes it non-existent (size-wise). The
window still appears in the taskbar & Alt+Tab window.

Dave
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