m_bitmap = new CBitmap;
 BYTE *p = new BYTE[2*n]; // n is width * height; basically sets up short
array for 16 bit
  if (p)
  {
        ZeroMemory(p, 2*n);
        int j = 1; // i'm gonna set every other bit at the moment.  I need
to convert what I assume is 8-bit grey to 16-bit grey
        for (int i = 0; i < n; i++)
       {
            p[j] = pImage[i]; // pImage is original BYTE data (pImage =
BYTE[n])
            j+=2;
       }

    m_bitmap->CreateCompatibleBitmap(&dc, nWidth, nHeight);
    m_bitmap->SetBitmapBits(2*n, p);
    delete p;
  }

If I set int j = 0 to set first byte of each short, I get a black screen.
If I allocate p as a short array, and set each element to (short)pImage[i],
I get a black screen.  When I create a DIB from this data (I swap the array
from top to bottom so it looks right), I get a picture of orange, green and
red points that looks vaguely like the source image, but isn't anywhere near
as clear as the bitmap (I need a DIB to save the bitmap to a file).

I'd like to this to show up in greyscale.  If I convert my bitmap back to
the original format, it appears perfectly in a viewer I have for that
format.  It's just me setting up the Windows display that is incorrect.  I
found some example data at http://www.*-*-*.com/
converting to greyscale, but it just leaves me with a black screen again (I
did use the 8,16,24-bit example).

Can anyone help me?  I must be getting the bits and bytes wrong somewhere,
but I can't figure it out.

Thanks...

Dave

// need to remap colors to greyscale
    short nColors[32];
    for (int i = 0; i < 32; i++)
    {
     nColors[i] = i + (i << 5) + (i << 10);
    }

    short* s = (short*)p;
    for (i = 0; i < nSize; i++)
    {
     s[i] = nColors[pImage[i]/5];
    }