Hi All,

I am trying my hand on operator overloading related to "cout<<endl;".
I write my own class as following but can't get operator << invoked on
my own endl. Could some anybody tell me what's wrong with my code.

I did it on VC6.0 starting with an empty console project with option
"Use MFC in a static libary"

Thanks in advance!!

Ray

#include <afx.h>

class COutObj  
{
public:
        COutObj():m_strOut(""){};
        virtual ~COutObj(){};

        COutObj & operator <<(CString str){
                m_strOut+=str;
                return *this;
        };
        COutObj & operator <<(COutObj& ( * f1)(COutObj& outs)){
                (*f1)(*this); return *this;
        }
        COutObj&  myendl(COutObj& outs){outs<<"myEndLine";return outs;}

private:
        CString m_strOut;

void main(){
        COutObj mycout;
        mycout<<"aaaaaaaa";     //ok
        mycout<<myendl;           //error C2065: 'myendl' : undeclared identifier

        mycout<<COutObj::myendl;
                //error C2678: binary '<<' : no operator defined
                //which takes a left-hand operand of
                //type 'class COutObj' (or there is no acceptable conversion)

If you want this to compile you have to define myendl as a regular
function outside the class definition.

You defined myendl as a non-static member function.
If you want this to compile you either have to define
it as a static member function

class COutObj  
{
public:
// ...
    static COutObj &  myendl(COutObj& outs) { outs << "myEndLine"; return outs; }

// ...

or define another operator << taking a pointer-to-member

class COutObj  
{
public:
// ...
    COutObj & operator << (COutObj & (COutObj::*pmf) (COutObj& outs)) {
        (this->*pmf)(*this);
        return *this;
    }
// ...

Sergei

Now I got a clear mind. Thank you very much for your quick response. I
do appreciate for your time.

ray