Hi!
This a very dangerous bug!!!

Run this code:

/////////////////
#include <stdio.h>
int main()
{
        int number;
        number = 1;

        if(1)
        {
                int number;
                number = 0;
        }

        if(number) // Put a breakpoint here and read the value of
                   // number. The watch says number = 0
                   // Althought the string will be printed. Corect.
                   // But the de{*filter*} can trap you by showing a wrong value
        {
                printf("This string will be printed\n");
        }
        return 0;

//////////////

florin

Hmmm...even if this is a bug, I'd be confused myself about which 'number'
to use...

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Eden Prairie, MN                  Personal Home Page:   http://www.*-*-*.com/ ~nde

"Question authority...and the authorities will end up questioning YOU!"
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