For a second degree equation (A*X^2 + B*X + C = 0), you would need to
"intelegently" apply the formula

X = ( -B + Sqrt( B^2 - 4*A*C) ) / (2*A)    and
X = ( -B  - Sqrt( B^2 - 4*A*C) ) / (2*A)

Note that you will not always have a "positive" solution to a second degree
equation.  The posibilites include:
1) two positive solution        (when B is negative and Sqrt(B^2-4AC) < B)
2) two negative solution        (when B is positive ans Sqrt(B^2-4AC) < B)
3) one positive solution and one negative solution (when Sqrt(B^2-4AC) > B)
4) two "imaginary" solutions  (when B^2-4AC is negative, because you can
not take the square root of a negative number).

Good Luck,
Joseph

   Root1 = ((-B) + Sqr((B^2) - 4AC) / 2A
   Root2 = ((-B) - Sqr((B^2) - 4AC) / 2A

  ...where A is 12.32, B is 179.24, and C is 958.1625, in your formula

        -- Jim

You may try third party custom controls.  I can't remember right off hand
where I saw a formula handling control.  You may try these companies:
        Visual Components
        Sheridan Systems
        Crescent
If they don't have an answer, they should lead you in the right direction.
Good luck.

I need to solve a second degree equation in Visual Basic .... something
like this:
12.32*X^2+179.24*X-958.1625=0
and I need Visual basic to choose the "positive"(X=4.157) solution from
the equation.
Can anyone HELP me?

--

Jo?o Varandas Marques
Parede - PORTUGAL

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