Help: how to solve a SECOND DEGREE equation in VB

Quote:

> I need to solve a second degree equation in Visual Basic .... something

> like this:

> 12.32*X^2+179.24*X-958.1625=0

> and I need Visual basic to choose the "positive"(X=4.157) solution from

> the equation.

Why not apply the quadratic formula, which gives both roots, and test the

results to see if you got a positive one? My memory of high-school math may

be faulty, but as I recall it:

Root1 = ((-B) + Sqr((B^2) - 4AC) / 2A

Root2 = ((-B) - Sqr((B^2) - 4AC) / 2A

...where A is 12.32, B is 179.24, and C is 958.1625, in your formula

-- Jim