Hi Stephan,
I think you should be able to insert a formula field that uses a
variable to keep the sum. Have the variable incremented by the value of the
distinct count.
Bob Holmes
Quote:
> I have a formula in my Report which usese the DistinctCount Function. I
need
> to build the sum of this Fomula. So far there is no way to do this
> regularly. Is there any way to solve this problem?
> Using Crystal Reports Version 6.
Sum of DistinctCount