Hi Stephan,

I think you should be able to insert a formula field that uses a

variable to keep the sum. Have the variable incremented by the value of the

distinct count.

Bob Holmes

Quote:

> I have a formula in my Report which usese the DistinctCount Function. I

need

> to build the sum of this Fomula. So far there is no way to do this

> regularly. Is there any way to solve this problem?

> Using Crystal Reports Version 6.