I have encountered what appears to be a bug in the MSComm control
included in the VB 4.0a CD release.

When the port is open, I close it (by setting the PortOpen property to
False), then attempt to reopen it less than a second or so later (by
setting the PortOpen property to True), and I get a runtime error that
says the "Port is already open".  

I verified that the PortOpen property is, indeed, returning a "False"
value before I set it to "True".

Has anyone encountered this behavior--and is there a workaround?  I need
to frequently open and close the port so it can be shared with another
process.

I'm using Version 1.0.2805 of MSCOMM32.OCX.

Thanks in advance!

 --Matt Thomas
   Codesmith, Inc.

I think you may have to:

   On Error GoTo Retry
   If MSComm1.PortOpen = False Then MSComm1.PortOpen = True
   'etc.
   Exit Sub

   Retry:
   If Err = 68 Then
       DoEvents
       DoEvents
       Resume
   Else
       MsgBox Error$
       Resume Next
   End If
End Sub
--
{*filter*} Grier
Hard & Software
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