VB.Net, RegEx Count

RegEx Count

Author	Message
Shawn B #1 / 3	RegEx Count How can I check to see if at least n characters are in the string but they can appear anywhere? A#2ksdfaAfa0 should return true because at least 2 CAPS are in there... I don't care where they occur, as long as there are at least 2 of them... Regex.IsMatch(text, "^([A-Z]?*){2}&") Thanks, Shawn
Tue, 13 Sep 2005 08:03:49 GMT

Stephen A. Weatherford [MSF #2 / 3	RegEx Count Regex.IsMatch(text, "([A-Y].){2}") -- Stephen Weatherford, VB .NET Team This posting is provided "AS IS" with no warranties, and confers no rights. \| A#2ksdfaAfa0 should return true because at least 2 CAPS are in there... \| \| I don't care where they occur, as long as there are at least 2 of them... \| \| \| \| Regex.IsMatch(text, "^([A-Z]?){2}&")
Wed, 14 Sep 2005 05:24:37 GMT

Shawn B #3 / 3	RegEx Count OMG... that's awesome... I thought I tried everything including that... and I did except I had the ^ in the front and that's why it failed. You know, I'll get the hang of this yet... BTW: www.planet-source-code.com search for "shawn bullock" in the .net or VB section... you'll see my validator class. in my new version I'll have this weekend I'll credit everyone for helping me on the particular RegEx's that they helped me in. Thanks, Shawn Quote: > Regex.IsMatch(text, "([A-Y].){2}") > -- > Stephen Weatherford, VB .NET Team > This posting is provided "AS IS" with no warranties, and confers no rights. > \| A#2ksdfaAfa0 should return true because at least 2 CAPS are in there... > \| > \| I don't care where they occur, as long as there are at least 2 of them... > \| > \| > \| > \| Regex.IsMatch(text, "^([A-Z]?){2}&")
Wed, 14 Sep 2005 06:22:11 GMT

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