> Every time I build my solution, I would like it to autoincrement the build
> number.  I used to do something similar in VB6, but can't figure out how
to
> increment the build (or private part) in VB.NET. Suggestions?

> It's in the Assembly.vb file.  Any asterisk in the version number will be
> automatically incremented.

> --

> Jim
> Jimco Add-ins
> http://www.jimcoaddins.com
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> > Every time I build my solution, I would like it to autoincrement the
build
> > number.  I used to do something similar in VB6, but can't figure out how
> to
> > increment the build (or private part) in VB.NET. Suggestions?

> Unfortunately, this is incorrect.

> I just compiled an app with AssemblyVersion("1.0.0.0") and the end result
> was just that - 1.0.0.0.

> I then changed it to '1.0.0.*' and re-compiled. The version was
> '1.0.0.15535' i.e. based on the time and thus meaningless.

> Jeff Law
> PPCInstall Developer
> http://www.ppcinstall.com

> > It's in the Assembly.vb file.  Any asterisk in the version number will
be
> > automatically incremented.

> > --

> > Jim
> > Jimco Add-ins
> > http://www.jimcoaddins.com
> > ==============================================
> > New FrontPage Add-ins Available:
> > Close All (with Save and Close All included)
> > ContextExport (Adds Export menu to context menus.)

> > New Visual Studio.NET Add-in:
> > Close All add-in for VS.NET now available!
> > ==============================================

> > > Every time I build my solution, I would like it to autoincrement the
> build
> > > number.  I used to do something similar in VB6, but can't figure out
how
> > to
> > > increment the build (or private part) in VB.NET. Suggestions?

> Jim,

> I've been using Build Numbers for many of my 30 years of programming!

> It seems somewhat illogical, however, that there is no means to actually
> increment i.e. add one to the specified value at each compilation.

> If you place a '*' in the 3rd position i.e. '1.0.*', you will get
> another time-related value put in there by the compiler. My example,
> using '1.0.*' 'incremented' from '0' to '863'. If thats what you mean by
> incrementing, I have to wonder about your math! :)

> Jeff Law
> DataMasta Limited
> New Zealand

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