The filename that I am searching for will look like this:
504456.08072002.txt

with the first 6 digits always the same, followed by the dot "." then
followed by 8 more digits (date) then ".txt"  Seems simple to me.

However, the pattern I'm using is failing on this filename: patrn =
"^504456\.\d{8}\.txt$"

Is there a better way of writing this?

Thanks,
Randy

with new regexp
  .pattern = "^504456\.\d{8}\.txt$"
  msgbox .test("504456.08072002.txt")
end with

--
One of the advantages of being disorderly is that one is constantly making
exciting discoveries. -A. A. Milne

=-=-=
Steve
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