Extra help.... 
Author Message
 Extra help....

Thanks to everyone who replied.

I have now moved on with my requirements !

Anyone ?


eg : no_duplicates([a,a,b,b,c,d,e,e],X) gives X=[a,b,c,d,e]

Thanks again in advance...

Mon, 12 Jul 1999 03:00:00 GMT  
 [ 1 post ] 

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