I would like to do something like the following but get a syntax error.

print ((1?OUT1:OUT2) "The expression was true\n");

where OUT1 and OUT2 are two different filehandles and the '1' would normally be  
replaced by an expression (probably something like (count % 2))

So what is wrong with this? Where am I going astray? Is there a better (read:  
working) way of doing this?

Respond by email and I will summarize.

Bryce Jasmer

$outfile = $count % 2 ? OUT1 : OUT2;
print $outfile "random output text.\n";

This is due to the fact that print and printf expect to see a filehandle and  
not an expression that ultimately results in a filehandle. Makes enough sense  
to me.

Thanks guys.

Just another C hacker converting to Perl,