calculating the julian day 
Author Message
 calculating the julian day

Skywatching is one thing you can do here in the desert southwest without
breaking your piggy bank, and I like to calculate where things are.  In
particular, I want to calculate when objects culminate, which is when they
cross my local meridian, which for solar system bodies means when they
appear directly south of me.

To that end, I'd like to calculate the julian day.  It's described on the
wiki: http://www.*-*-*.com/

This is what I have so far:

implicit none

real :: a, y, m, jdn, jd
integer :: day, month, year

INTEGER date_time(8)
CHARACTER(LEN=10) big_ben(3)

          CALL DATE_AND_TIME(big_ben(1), big_ben(2), big_ben(3), date_time)
          PRINT *,'date_time array values:'
          PRINT *,'year=',date_time(1)
          PRINT *,'month_of_year=',date_time(2)
          PRINT *,'day_of_month=',date_time(3)
          PRINT *,'time difference in minutes=',date_time(4)
          PRINT *,'hour of day=',date_time(5)
          PRINT *,'minutes of hour=',date_time(6)
          PRINT *,'seconds of minute=',date_time(7)
          PRINT *,'milliseconds of second=',date_time(8)
          PRINT *, 'DATE=',big_ben(1)
          PRINT *, 'TIME=',big_ben(2)
          PRINT *, 'ZONE=',big_ben(3)

day = date_time(3)
month = date_time(2)
year = date_time(1)

a = (14.0 - 1.0*month)/12.0
y = year + 4800 - a
m = month + (12* a) - 3
jdn = day + (((153* m) + 2) / 5.0) + (365 * y) + &
     & (y / 4.0) - 32083

print *, "jdn is ", jdn

endprogram

! g95 jul1.f95 -o t.exe

C:\MinGW\source>t
 date_time array values:
 year= 2009
 month_of_year= 1
 day_of_month= 30
 time difference in minutes= -420
 hour of day= 21
 minutes of hour= 25
 seconds of minute= 55
 milliseconds of second= 546
 DATE=20090130
 TIME=212555.546
 ZONE=-0700
 jdn is  2454875.5

C:\MinGW\source>

The correct number is 2454862, so this needs some work.  I have a couple
questions:

q1)  Has anyone done this before in fortran?

q2)  A calculation like this intermixes reals and integers.  a is likely a
non-integer rational.  I don't know how promotions go in fortran.  Is this
the best way to write it:

a = (14.0 - 1.0*month)/12.0

q3) I would think that there are 24 valid julian times at any moment, given
which 15 slice one inhabits.  Where is the greatest one?

Thanks for your comment.
--
larry gates

The way I see it, if you declare something portable, you'll always be
wrong, and if you declare it non-portable, you'll always be right.  :-)



Wed, 20 Jul 2011 12:32:41 GMT  
 calculating the julian day

Quote:

> q1)  Has anyone done this before in fortran?

I think there is an example in NUMERICAL RECIPES.


Wed, 20 Jul 2011 19:15:19 GMT  
 calculating the julian day


Quote:
>To that end, I'd like to calculate the julian day.  It's described on the
>wiki: http://en.wikipedia.org/wiki/Julian_day

Have a look at datesub.f90 on Alan Miller's website
http://users.bigpond.net.au/amiller/

or H.D.Knoble's website
http://ftp.cac.psu.edu/pub/ger/fortran/hdk/00-index.txt

--
Clive Page



Wed, 20 Jul 2011 19:22:29 GMT  
 calculating the julian day
you may also be interested in a modern version of this.
we turned it into a date class.

this is taken from our book.

http://www.fortranplus.co.uk/fortran_books.html

and the code is at

http://www.fortranplus.co.uk/resources/ch2611.f90

cheers

ian


Quote:


> >To that end, I'd like to calculate the julian day. ?It's described on the
> >wiki:http://en.wikipedia.org/wiki/Julian_day

> Have a look at datesub.f90 on Alan Miller's websitehttp://users.bigpond.net.au/amiller/

> or H.D.Knoble's websitehttp://ftp.cac.psu.edu/pub/ger/fortran/hdk/00-index.txt

> --
> Clive Page



Wed, 20 Jul 2011 19:45:57 GMT  
 calculating the julian day
On Sat, 31 Jan 2009 11:15:19 +0000 (UTC), Phillip Helbig---remove CLOTHES

Quote:



>> q1)  Has anyone done this before in fortran?

> I think there is an example in NUMERICAL RECIPES.

Thanks for your response, phil.  I would be reliant on UNM's library for
that, and they only have one of the two, so it's a bit of a crapshoot as
well as it being closed on saturday night.

Last time I went down, I asked at the desk of the CS dept how I might find
Brian T. Smith, professor emeritus and co-author of my current for fortran
reading: _The Fortran 2003 Handbook_.  He doesn't keep any office hours,
but they gave me his home phone number!

I do want to call him, invite him to a coffeehouse, and ask him about the
fortran he's seen and written about.  I'm gonna wait till I finish the
book, though, so I wouldn't ask something stupid.

--
larry gates

People who understand context would be steamed to have someone else
dictating how they can call it.



Thu, 21 Jul 2011 09:36:12 GMT  
 calculating the julian day

Quote:

> q3) I would think that there are 24 valid julian times at any moment, given
> which 15 slice one inhabits.  Where is the greatest one?

Wrong for at least 2 reasons. 1. Some places are never an exact number
of hours ahead of Greenwich, e.g. South Australia. 2. New Zealand,
which is exactly 12h ahead for half the year, is 13h ahead when we are
on summer time. (Then there's the Chatham islands, 45 min ahead of the
rest of NZ)

John Harper



Thu, 21 Jul 2011 12:01:55 GMT  
 calculating the julian day

Quote:



>>To that end, I'd like to calculate the julian day.  It's described on the
>>wiki: http://www.*-*-*.com/

> Have a look at datesub.f90 on Alan Miller's website
> http://www.*-*-*.com/

> or H.D.Knoble's website
> http://www.*-*-*.com/

Thanks, Clive, I'd never seen Skip's site before.  What you have to do is
select the file you want and cut_and_paste it into the end of url so as to
ace the index after /hdk/.

http://www.*-*-*.com/

(I'd never thought of a folder name in an url as a regex before.)

Anyways, I think you can tell that I'm cleaning my house while I get this
typed up.  I do a lot better with typing on this 2 month 24 day since Miss
Nguyen ran me over in her car because she wasn't looking in the direction
she was accelerating her vehicle.  She tells the cop I ran into her and
somehow hasn't directed her insurance to pick up my medical bills.  I've
been thinking an awful lot about that insurance adjuster's face needing an
adjustment by a two by three by four, maybe even five.

C:\MinGW\source> g95 skip1.f -o y.exe
C:\DOCUME~1\dan\LOCALS~1\Temp/ccGeaMPU.o:skip1.f:(.text+0x20): undefined
referen
ce to `getdat_'

C:\MinGW\source>

So getdat needs a year, a month and a day.  I post source after the sig
that I think relevant.

Furthermore, Chicago has something for B-rod's ukainian friends.
--
larry gates

If you want to program in C, program in C.  It's a nice language.  I
use it occasionally...   :-)

C This file: http://www.*-*-*.com/
C
C======DATESUB.FOR with Sample Drivers.
C      COLLECTED AND PUT TOGETHER JANUARY 1972, H. D. KNOBLE .
C      ORIGINAL REFERENCES ARE CITED IN EACH ROUTINE.
C
      INTEGER YYYY,MM,DD,JD,WD,DDD,MMA,DDA,NDIFF,I
      INTEGER*2 YYYY2,MM2,DD2
C
C====IDAY IS A COMPANION TO CALEND; GIVEN A CALENDAR DATE, YYYY, MM,
C           DD, IDAY IS RETURNED AS THE DAY OF THE YEAR.
C           EXAMPLE: IDAY(1984,4,22)=113
      IDAY(YYYY,MM,DD)=3055*(MM+2)/100-(MM+10)/13*2-91
     ,                 +(1-(MOD(YYYY,4)+3)/4+(MOD(YYYY,100)+99)/100
     ,                 -(MOD(YYYY,400)+399)/400)*(MM+10)/13+DD
C
C====IZLR(YYYY,MM,DD) GIVES THE WEEKDAY NUMBER 0=SUNDAY, 1=MONDAY,
C      ... 6=SATURDAY.  EXAMPLE: IZLR(1970,1,1)=4=THURSDAY
      IZLR(YYYY,MM,DD)=MOD((13*(MM+10-(MM+10)/13*12)-1)/5+DD+77
     ,            +5*(YYYY+(MM-14)/12-(YYYY+(MM-14)/12)/100*100)/4
     ,            + (YYYY+(MM-14)/12)/400-(YYYY+(MM-14)/12)/100*2,7)
C
C  Compute date this year for changing clocks back to EST.
C  See program: estdst.f90
C
C  Is this a leap year? I.e. is 12/31/yyyy the 366th day of the year?
      CALL GETDAT(YYYY2,MM2,DD2)
C---GETDAT is builtin using some Compilers.
      YYYY=YYYY2
      IF(IDAY(YYYY,12,31).EQ.366) THEN
         WRITE(*,*) YYYY,' is a Leap Year'
      ELSE
         WRITE(*,*) YYYY,' is not a Leap Year'
      ENDIF
C
C  DAYSUB SHOULD RETURN: 1970, 1, 1, 4, 1
      CALL DAYSUB(JD(1970,1,1),YYYY,MM,DD,WD,DDD)
      IF(YYYY.NE.1970.OR.MM.NE.1.OR.DD.NE.1.OR.WD.NE.4.OR.DDD.NE.1)
     *  THEN
        WRITE(*,*)'DAYSUB Failed; YYYY,MM,DD,WD,DDD=',YYYY,MM,DD,WD,DDD
        STOP 1
      ENDIF
C  DIFFERENCE BETWEEN TWO SAME MONTHS AND DAYS OVER 1 LEAP YEAR IS 366.
      NDIFF=NDAYS(5,22,1984,5,22,1983)
      IF(NDIFF.NE.366) THEN
        WRITE(*,*) 'NDAYS FAILED; NDIFF=',NDIFF
      ELSE
C  RECOVER MONTH AND DAY FROM YEAR AND DAY NUMBER.
        CALL CALEND(YYYY,DDD,MMA,DDA)
        IF(MMA.NE.1.AND.DDA.NE.1) THEN
          WRITE(*,*) 'CALEND FAILED; MMA,DDA=',MMA,DDA
                                  ELSE
          WRITE(*,*) '** DATE MANIPULATION SUBROUTINES SIMPLE TEST OK.'
        END IF
      END IF
      STOP
      END
      SUBROUTINE CALEND(YYYY,DDD,MM,DD)
C=====CALEND WHEN GIVEN A VALID YEAR, YYYY, AND DAY OF THE
C             YEAR, DDD, RETURNS THE MONTH, MM, AND DAY OF THE
C             MONTH, DD.
C             SEE ACM ALGORITHM 398, TABLELESS DATE CONVERSION, BY
C            {*filter*} STONE, CACM 13(10):621.
      INTEGER YYYY,DDD,MM,DD,T
      T=0
      IF(MOD(YYYY,4).EQ.0) T=1
C-------THE FOLLOWING STATEMENT IS NECESSARY IF YYYY IS LESS TNAN
C           1900 OR GREATER THAN 2100.
      IF(MOD(YYYY,400).NE.0.AND.MOD(YYYY,100).EQ.0) T=0
      DD=DDD
      IF(DDD.GT.59+T) DD=DD+2-T
      MM=((DD+91)*100)/3055
      DD=(DD+91)-(MM*3055)/100
      MM=MM-2
C-------MM WILL BE CORRECT IFF DDD IS CORRECT FOR YYYY.
      IF(MM.GE.1 .AND. MM.LE.12) RETURN
      WRITE(*,1) DDD
1     FORMAT('0$$$CALEND: DAY OF THE YEAR INPUT =',I11,
     ,       ' IS OUT OF RANGE.')
      STOP 8
      END
      SUBROUTINE CDATE(JD,YYYY,MM,DD)
C=====GIVEN A JULIAN DAY NUMBER, NNNNNNNN, YYYY,MM,DD ARE RETURNED AS
C              AS THE CALENDAR DATE. JD=NNNNNNNN IS THE JULIAN DATE
C              FROM AN EPOCK IN THE VERY DISTANT PAST.  SEE CACM
C              1968 11(10):657, LETTER TO THE EDITOR BY FLIEGEL AND
C              VAN FLANDERN.
C    EXAMPLE CALL CDATE(2440588,YYYY,MM,DD) RETURNS 1970 1 1 .
C
      INTEGER JD,YYYY,MM,DD,L,N
      L=JD+68569
      N=4*L/146097
      L=L-(146097*N + 3)/4
      YYYY=4000*(L+1)/1461001
      L=L-1461*YYYY/4+31
      MM=80*L/2447
      DD=L-2447*MM/80
      L=MM/11
      MM=MM + 2 - 12*L
      YYYY=100*(N-49) + YYYY + L
      RETURN
      END
      SUBROUTINE DAYSUB(JD,YYYY,MM,DD,WD,DDD)
C=====GIVEN JD, A JULIAN DAY # (SEE ASF JD), THIS ROUTINE
C        CALCULATES DD, THE DAY NUMBER OF THE MONTH; MM, THE MONTH
C        NUMBER; YYYY THE YEAR; WD THE WEEKDAY NUMBER, AND DDD
C        THE DAY NUMBER OF THE YEAR.
C        ARITHMETIC STATEMENT FUNCTIONS 'IZLR' AND 'IDAY' ARE TAKEN
C        FROM REMARK ON ALGORITHM 398, BY J. DOUGLAS ROBERTSON,
C        CACM 15(10):918.
C
C   EXAMPLE: CALL DAYSUB(2440588,YYYY,MM,DD,WD,DDD) YIELDS 1970 1 1 4 1.
C
      INTEGER JD,YYYY,MM,DD,WD,DDD
C
C====IZLR(YYYY,MM,DD) GIVES THE WEEKDAY NUMBER 0=SUNDAY, 1=MONDAY,
C      ... 6=SATURDAY.  EXAMPLE: IZLR(1970,1,1)=4=THURSDAY
C
      IZLR(YYYY,MM,DD)=MOD((13*(MM+10-(MM+10)/13*12)-1)/5+DD+77
     ,            +5*(YYYY+(MM-14)/12-(YYYY+(MM-14)/12)/100*100)/4
     ,            + (YYYY+(MM-14)/12)/400-(YYYY+(MM-14)/12)/100*2,7)
C
C====IDAY IS A COMPANION TO CALEND; GIVEN A CALENDAR DATE, YYYY, MM,
C           DD, IDAY IS RETURNED AS THE DAY OF THE YEAR.
C           EXAMPLE: IDAY(1984,4,22)=113
C
      IDAY(YYYY,MM,DD)=3055*(MM+2)/100-(MM+10)/13*2-91
     ,                 +(1-(MOD(YYYY,4)+3)/4+(MOD(YYYY,100)+99)/100
     ,                 -(MOD(YYYY,400)+399)/400)*(MM+10)/13+DD
C
      CALL CDATE(JD,YYYY,MM,DD)
      WD=IZLR(YYYY,MM,DD)
      DDD=IDAY(YYYY,MM,DD)
      RETURN
      END
      FUNCTION JD(YYYY,MM,DD)
      INTEGER YYYY,MM,DD
C              DATE ROUTINE JD(YYYY,MM,DD) CONVERTS CALENDER DATE TO
C              JULIAN DATE.  SEE CACM 1968 11(10):657, LETTER TO THE
C              EDITOR BY HENRY F. FLIEGEL AND THOMAS C. VAN FLANDERN.
C    EXAMPLE JD(1970,1,1)=2440588
      JD=DD-32075+1461*(YYYY+4800+(MM-14)/12)/4
     ,         +367*(MM-2-((MM-14)/12)*12)/12-3*
     ,         ((YYYY+4900+(MM-14)/12)/100)/4
      RETURN
      END
      FUNCTION NDAYS(MM1,DD1,YYYY1, MM2,DD2,YYYY2)
      INTEGER YYYY1,MM1,DD1,YYYY2,MM2,DD2
C=====NDAYS IS RETURNED AS THE NUMBER OF DAYS BETWEEN TWO
C              DATES; THAT IS  MM1/DD1/YYYY1 MINUS MM2/DD2/YYYY2,
C              WHERE DATEI AND DATEJ HAVE ELEMENTS MM, DD, YYYY.
C-------NDAYS WILL BE POSITIVE IFF DATE1 IS MORE RECENT THAN DATE2.
      NDAYS=JD(YYYY1,MM1,DD1)-JD(YYYY2,MM2,DD2)
      RETURN
      END

c g95 skip1.f -o y.exe



Thu, 21 Jul 2011 14:22:02 GMT  
 calculating the julian day

Quote:


>> q3) I would think that there are 24 valid julian times at any moment, given
>> which 15 slice one inhabits.  Where is the greatest one?

> Wrong for at least 2 reasons. 1. Some places are never an exact number
> of hours ahead of Greenwich, e.g. South Australia. 2. New Zealand,
> which is exactly 12h ahead for half the year, is 13h ahead when we are
> on summer time. (Then there's the Chatham islands, 45 min ahead of the
> rest of NZ)

> John Harper

But jtime in hawaii is either less than or greater than you.

This notion speaks to "order."
--
larry gates

It'd be really nice to find a way to explain continuations to people
without inflicting the typical torturous explanations on people who
aren't interested in brain pretzels.
             -- Larry Wall



Thu, 21 Jul 2011 14:43:40 GMT  
 calculating the julian day


Quote:

>Last time I went down, I asked at the desk of the CS dept how I might find
>Brian T. Smith, professor emeritus and co-author of my current for fortran
>reading: _The Fortran 2003 Handbook_.  He doesn't keep any office hours,
>but they gave me his home phone number!

>I do want to call him, invite him to a coffeehouse, and ask him about the
>fortran he's seen and written about.  I'm gonna wait till I finish the
>book, though, so I wouldn't ask something stupid.

He won't get sniffy - he's a good guy.  Send my regards if you do.

Regards,
Nick Maclaren.



Thu, 21 Jul 2011 17:55:31 GMT  
 calculating the julian day
Hi!

In a discussion on this list named "Date representation", starting 11
september 2008,
I showed an example of my F90 implementation of date-time
representation and conversion.
After some digestion by Arjen Markus, you can download the Module from
http://flibs.sf.net. With copy/paste from that discussion here is the
example:

USE libdate

TYPE(DateType) :: t,t_stop

t      = DateType(1994,1, 1, 0,0) ! 1 january 1994
t_stop = DateType(2008,9,11,12,0) ! noon today

DO WHILE (t.LT.t_stop)
  ......

  WRITE(*,*) DOY(t) ! Integer number Day Of Year

  ......

  t = t + DateType(0,0,0,1,0) ! timestep of 1 hour
ENDDO

Another function from LibDate is function Date2Julian(t).
Try and see! The code is there and free!

Regards,

Arjan



Fri, 22 Jul 2011 01:23:41 GMT  
 calculating the julian day

Quote:

> you may also be interested in a modern version of this.
> we turned it into a date class.

> this is taken from our book.

> http://www.*-*-*.com/

> and the code is at

> http://www.*-*-*.com/

> cheers

> ian

Looks great, Ian, I'll put your book in queue to buy.  I much prefer free
form.  I can't shake the feeling that f77 code is YELLING AT ME.

C:\MinGW\source>g95 skip2.f90 -o u.exe

C:\MinGW\source>u
 date_stamp = Sunday,  1 February 2009
 date_stamp =  1 February 2009
 date_stamp = Sunday,  1 Feb 2009
 date_stamp =  1 Feb 2009
 turn clocks ahead to dst on:
 5  april  2009
 2009  is not a leap year
 ** date manipulation subroutines
 ** simple test ok.

C:\MinGW\source>

That's a {*filter*} little program there.  It takes me a bit to figure out how to
call things, but it's all there for me to tap into.  Source listing after
sig.

--
larry gates

It's, uh, pseudo code.  Yeah, that's the ticket...
[...]
And "unicode" is pseudo code for $encoding.  :-)

MODULE date_module
!  Collected and put together january 1972,
!  h. d. knoble.
!  Original references are cited in each routine.
!  Code converted using to_f90 by alan miller
!  Date: 1999-12-22  time: 10:23:47
!  Compatible with imagine1 f compiler: 2002-07-19
!  At this time the functions and
!  subroutines were as described below
!  FUNCTION iday(yyyy, mm, dd) RESULT(ival)
!  FUNCTION izlr(yyyy, mm, dd) RESULT(ival)
!  SUBROUTINE calend(yyyy, ddd, mm, dd)
!  SUBROUTINE cdate(jd, yyyy, mm, dd)
!  SUBROUTINE daysub(jd, yyyy, mm, dd, wd, ddd)
!  FUNCTION jd(yyyy, mm, dd) RESULT(ival)
!  FUNCTION ndays(mm1, dd1, yyyy1,
!     mm2, dd2, yyyy2) RESULT(ival)
!  SUBROUTINE date_stamp( string, want_day, short )
!  Code converted by ian chivers and jane sleightholme
!  November 2004 - May 2005
!  The changes are to go from
!  working with integer variables
!  for year, day and month to
!  user defined date variables.
! .. Implicit None Statement ..
  IMPLICIT NONE
! ..
! .. Default Accessibility ..
  PRIVATE
! ..
! .. Derived Type Declarations ..
  TYPE, PUBLIC :: date
    PRIVATE
    INTEGER :: day
    INTEGER :: month
    INTEGER :: year
  END TYPE date
! ..
! .. Public Statements ..
  PUBLIC :: calendar_to_julian,&
    date_, &
    date_stamp, &
    date_to_day_in_year, &
    date_to_weekday_number, &
    get_day, &
    get_month, &
    get_year, &
    julian_to_date, &
    julian_to_date_and_week_and_day, &
    ndays, &
    year_and_day_to_date
! ..
!  The above are the contained
!  functions and subroutines
!  in this module.
!  Here is a short description of each one
!    date_to_day_in_year     - function
!      returns the day in the year
!      original arguments of day,month,year
!      now date
!      dayinyear
!    date_to_weekday_number  - function  
!      returns the week day number
!      original argument d,m,y
!      now date
!      weekdaynum
!    year_and_day_to_date    - subroutine
!      returns the day and month from
!      year and day in year
!    julian_to_date          - subroutine
!      returns a year_and_day_to_datear date from
!      a julian date
!    ndays                   - function
!      returns the number of days between
!      two dates
!    julian_to_date_and_week_and_day   - subroutine
!      given a julian day this routine
!      calculates year, month day and
!      week day number and day number
!    calendar_to_julian      - function
!      returns julian date from
!      year_and_day_to_datear date
CONTAINS

! arithmetic functions "izlr" and "iday"
! are taken from remark on
! algorithm 398, by j. douglas robertson,
! cacm 15(10):918.

  FUNCTION date_to_day_in_year(x)
! Convert from date to day in year
! .. Implicit None Statement ..
    IMPLICIT NONE
! ..
! .. Function Return Value ..
    INTEGER :: date_to_day_in_year
! ..
! .. Structure Arguments ..
    TYPE (date), INTENT (IN) :: x
! ..
! .. Intrinsic Functions ..
    INTRINSIC modulo
! ..
    date_to_day_in_year = 3055*(x%month+2)/100 &
      - (x%month+10)/13*2 - 91 + &
      (1-(modulo(x%year,4)+3)/4 &
      + (modulo(x%year,100)+99)/100 &
      - (modulo(x%year, &
      400)+399)/400)*(x%month+10)/13 + x%day

  END FUNCTION date_to_day_in_year

  FUNCTION date_to_weekday_number(x)
! .. Implicit None Statement ..
    IMPLICIT NONE
! ..
! .. Function Return Value ..
    INTEGER :: date_to_weekday_number
! ..
! .. Structure Arguments ..
    TYPE (date), INTENT (IN) :: x
! ..
! .. Intrinsic Functions ..
    INTRINSIC modulo
! ..
    date_to_weekday_number = &
      modulo((13*(x%month+10 &
      -(x%month+10)/13*12)-1)/5+x &
      %day+77+5*(x%year+(x%month-14)/12 &
      -(x%year+(x%month-14)/12)/100*100)/4 &
      +(x%year+(x%month-14)/12)/400 &
      -(x%year+(x%month-14)/12)/100*2,7)

  END FUNCTION date_to_weekday_number

  FUNCTION year_and_day_to_date(year,day) RESULT (x)
! .. Implicit None Statement ..
    IMPLICIT NONE
! ..
! .. Function Return Value ..
    TYPE (date) :: x
! ..
! .. Scalar Arguments ..
    INTEGER, INTENT (IN) :: day, year
! ..
! .. Local Scalars ..
    INTEGER :: t
! ..
! .. Intrinsic Functions ..
    INTRINSIC modulo
! ..
    x%year = year
    t = 0
    IF (modulo(year,4)==0) THEN
      t = 1
    END IF

!------the following statement is
! necessary IF year is < 1900 or > 2100.

    IF (modulo(year,400)/=0 &
      .AND. modulo(year,100)==0) THEN
      t = 0
    END IF

    x%day = day

    IF (day>59+t) THEN
      x%day = x%day + 2 - t
    END IF

    x%month = ((x%day+91)*100)/3055
    x%day = (x%day+91) - (x%month*3055)/100
    x%month = x%month - 2

    IF (x%month>=1 .AND. x%month<=12) THEN
      RETURN
    END IF

! x%month will be correct
! iff day is correct for year.

    WRITE (unit=*,fmt='(a,i11,a)') &
    '$$year_and_day_to_date: day of the year input =', &
    day, ' is out of range.'

  END FUNCTION year_and_day_to_date

  FUNCTION julian_to_date(julian) RESULT (x)
! Given a julian day number the date is returned.
! julian is the julian date from an epocch
! in the very distant past.  see cacm 1968 11(10):657,
! letter to the editor by fliegel and van flandern.
! .. Implicit None Statement ..
    IMPLICIT NONE
! ..
! .. Scalar Arguments ..
    INTEGER, INTENT (IN) :: julian
! ..
! .. Local Scalars ..
    INTEGER :: l, n
! ..
! .. Function Return Value ..
    TYPE (date) :: x
! ..
    l = julian + 68569
    n = 4*l/146097
    l = l - (146097*n+3)/4
    x%year = 4000*(l+1)/1461001
    l = l - 1461*x%year/4 + 31
    x%month = 80*l/2447
    x%day = l - 2447*x%month/80
    l = x%month/11
    x%month = x%month + 2 - 12*l
    x%year = 100*(n-49) + x%year + l

  END FUNCTION julian_to_date

  SUBROUTINE &
  julian_to_date_and_week_and_day(jd,x,wd,ddd)
! given jd, a julian day # (see asf jd),
! this routine calculates dd,
! the day number of the month;
! mm, the month number; yyyy the year;
! wd the weekday number, and
! ddd the day number of the year.
! example:
! CALL julian_to_date_and_week_and_day
! (2440588, yyyy, mm, dd, wd, ddd)
! yields 1970 1 1 4 1.
! .. Implicit None Statement ..
    IMPLICIT NONE
! ..
! .. Scalar Arguments ..
    INTEGER, INTENT (OUT) :: ddd, wd
    INTEGER, INTENT (IN) :: jd
! ..
! .. Structure Arguments ..
    TYPE (date), INTENT (OUT) :: x
! ..
    x = julian_to_date(jd)
    wd = date_to_weekday_number(x)
    ddd = date_to_day_in_year(x)

  END SUBROUTINE julian_to_date_and_week_and_day

  FUNCTION calendar_to_julian(x) RESULT (ival)
! .. Implicit None Statement ..
    IMPLICIT NONE
! ..
! .. Function Return Value ..
    INTEGER :: ival
! ..
! .. Structure Arguments ..
    TYPE (date), INTENT (IN) :: x
! ..
! date routine calendar_to_julian converts date to
! julian date.  see cacm 1968 11(10):657,
! letter to the
! editor by henry f. fliegel and
! thomas c. van flandern.
! example calendar_to_julian(1970, 1, 1) = 2440588
    ival = x%day - 32075 &
      + 1461*(x%year+4800+(x%month-14)/12)/4 + &
      367*(x%month-2-((x%month-14)/12)*12)/12 &
      - 3*((x%year+4900+(x%month-14)/ &
      12)/100)/4

  END FUNCTION calendar_to_julian

  FUNCTION ndays(date1,date2)
! .. Implicit None Statement ..
    IMPLICIT NONE
! ..
! .. Function Return Value ..
    INTEGER :: ndays
! ..
! .. Structure Arguments ..
    TYPE (date), INTENT (IN) :: date1, date2
! ..
! dates; that is  mm1/dd1/yyyy1 minus
! mm2/dd2/yyyy2,
! where datei and datej have elements mm, dd, yyyy.
! ndays will be positive iff
! date1 is more recent than date2.
    ndays = calendar_to_julian(date1) &
      - calendar_to_julian(date2)

  END FUNCTION ndays

  SUBROUTINE date_stamp(string,want_day,short)
! Returns the current date as a character string
! e.g.
! want_day     short      string
! .TRUE.      .TRUE.      Thursday, 23 Dec 1999
! .TRUE.      .FALSE.     Thursday, 23 December 1999  
!  <- defaul/
! .FALSE.     .TRUE.      23 Dec 1999
! .FALSE.     .FALSE.     23 December 1999
! .. Implicit None Statement ..
    IMPLICIT NONE
! ..
! .. Scalar Arguments ..
    LOGICAL, OPTIONAL, INTENT (IN) :: short, want_day
    CHARACTER (*), INTENT (OUT) :: string
! ..
! .. Local Scalars ..
    INTEGER :: pos
    LOGICAL :: sh, want_d
! ..
! .. Local Arrays ..
    INTEGER :: val(8)
    CHARACTER (9) :: day(0:6) = (/ 'Sunday   ' &
                                 , 'Monday   ' &
                                 , 'Tuesday  ' &
                                 ,  'Wednesday' &
                                 , 'Thursday ' &
                                 , 'Friday   ' &
                                 , 'Saturday '/)
    CHARACTER (9) :: month(1:12) = &
       (/ 'January  ' &
        , 'February ' &
         , 'March    ' &
         , 'April    ' &
         , 'May      ' &
         , 'June     ' &
         , 'July     ' &
         , 'August   ' &
         , 'September' &
         , 'October  ' &
         , 'November ' &
         , 'December '/)
...

read more »



Fri, 22 Jul 2011 04:31:52 GMT  
 calculating the julian day

Quote:



>>Last time I went down, I asked at the desk of the CS dept how I might find
>>Brian T. Smith, professor emeritus and co-author of my current for fortran
>>reading: _The Fortran 2003 Handbook_.  He doesn't keep any office hours,
>>but they gave me his home phone number!

>>I do want to call him, invite him to a coffeehouse, and ask him about the
>>fortran he's seen and written about.  I'm gonna wait till I finish the
>>book, though, so I wouldn't ask something stupid.

> He won't get sniffy - he's a good guy.  Send my regards if you do.

> Regards,
> Nick Maclaren.

Maybe I'll call him sooner.  In social situations, I'm painfully shy for no
apparent reason.
--
larry gates

There are still some other things to do, so don't think if I didn't fix
your favorite bug that your bug report is in the bit bucket.  (It may be,



Fri, 22 Jul 2011 04:35:45 GMT  
 calculating the julian day

Quote:

> Hi!

> In a discussion on this list named "Date representation", starting 11
> september 2008,
> I showed an example of my F90 implementation of date-time
> representation and conversion.
> After some digestion by Arjen Markus, you can download the Module from
> http://flibs.sf.net. With copy/paste from that discussion here is the
> example:

> USE libdate

> TYPE(DateType) :: t,t_stop

> t      = DateType(1994,1, 1, 0,0) ! 1 january 1994
> t_stop = DateType(2008,9,11,12,0) ! noon today

> DO WHILE (t.LT.t_stop)
>   ......

>   WRITE(*,*) DOY(t) ! Integer number Day Of Year

>   ......

>   t = t + DateType(0,0,0,1,0) ! timestep of 1 hour
> ENDDO

> Another function from LibDate is function Date2Julian(t).
> Try and see! The code is there and free!

> Regards,

> Arjan

Arjan,

I didn't see a date manipulation prog at that site.

You speak of Arjen in the third person.  I always thought that you were
Arjen, maybe a little jazzed up on Jaegermeister and a spliffy.

It's a football holy day here in the states.  I'm taking the cardinals and
the points.  Peace.
--
larry gates

"Help save the world!"              -- Larry Wall in README



Fri, 22 Jul 2011 04:52:27 GMT  
 calculating the julian day

Quote:
> I didn't see a date manipulation prog at that site.

On http://flibs.sourceforge.net/ Arjen provides you with a whole bunch
of categories.
Check out "Computational facilities" and the last contribution in this
category is "libdate".

Quote:
> You speak of Arjen in the third person. ?I always thought that you were Arjen,

Nope! Our names are similar (but not identical!). In the Netherlands
you can
find Arjan, Arjen, Arijan, Arijjan, Arie-Jan, Arien, Arian, Adriaan
and many more.
Sorry for the confusion, but Arjan <> Arjen!

Quote:
> maybe a little jazzed up on Jaegermeister and a spliffy.

Cheers!

Arjan



Fri, 22 Jul 2011 17:58:24 GMT  
 calculating the julian day
Larry

If you haven't seen it already, you might want to dig out a copy of

http://emr.cs.iit.edu/home/reingold/calendar-book/index.shtml

from your local library.  I have the 1st edition and it's an excellent
source of algorithms for the topic.

Regards

Mark Westwood


Quote:
> > I didn't see a date manipulation prog at that site.

> Onhttp://flibs.sourceforge.net/Arjen provides you with a whole bunch
> of categories.
> Check out "Computational facilities" and the last contribution in this
> category is "libdate".

> > You speak of Arjen in the third person. ?I always thought that you were Arjen,

> Nope! Our names are similar (but not identical!). In the Netherlands
> you can
> find Arjan, Arjen, Arijan, Arijjan, Arie-Jan, Arien, Arian, Adriaan
> and many more.
> Sorry for the confusion, but Arjan <> Arjen!

> > maybe a little jazzed up on Jaegermeister and a spliffy.

> Cheers!

> Arjan



Fri, 22 Jul 2011 18:13:36 GMT  
 
 [ 32 post ]  Go to page: [1] [2] [3]

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