Well, i'm a C beginner.
i've just switched from Pascal.
to the point:

after writing the following lines:
(where v is a one-dimension array, size 7)
printf ("enter the numbers ");
for (count=0;count<=6;count++)
     scanf("%d",v[count]

everything runs correctly, but the nubers i type, won't stay in
v[count]. it remains zero. why ?
thanx in advnace
Mr. Amos Freund

"200Kph on a big bore UJM. THE fun!"

C-compiler cannot detect such error, because scanf defined as: int scanf (const char * format, ... );
Good luck with C
Vladimir

What else do you have going on? How did you initialize the array? This
looks correct to me.(well except for no paras-which I assume was just
for posting)
Scott D.

Try
 scanf("%d", &v[count] );

h.f.s.
cc,f'up
--
Hans Friedrich Steffani
Institut fuer Elektrische Maschinen und Antriebe, TU Chemnitz-Zwickau

http://www.tu-chemnitz.de/~hfst/

Incidently, scanf() is often unpleasant for direct user input - unexpected
input (letters when it expects a number, for example) can cause problems.  It
may be better to get a whole line with fgets(), then you can examine it at your
leisure, scan it with sscanf(), pick it apart with strtok(), etc.  Generally
much easier to recover from errors this way...

Peter Bennett VE7CEI                | Vessels shall be deemed to be in sight


TRIUMF, Vancouver, B.C., Canada     |                          ColRegs 3(k)
GPS and NMEA info and programs: ftp://sundae.triumf.ca/pub/peter/index.html
or: ftp://ftp-i2.informatik.rwth-aachen.de/pub/arnd/GPS/peter/index.html
or: http://vancouver-webpages.com/peter/index.html

19:10:08 GMT):

:Well, i'm a C beginner.
:i've just switched from pascal.
:to the point:

:after writing the following lines:
:(where v is a one-dimension array, size 7)
:printf ("enter the numbers ");

It is a good idea to follow the above with
    fflush(stdout);
to insure that the output appears before you attempt to read below

:for (count=0;count<=6;count++)
:     scanf("%d",v[count]

The function scanf() needs to know where to put the read data, not its
value.  v[count] as a parameter to scanf() is just the value that is already
in v[count].  If you had been running on a more sophisticated machine, you
would have encountered an addressing error on running this; with a better
compiler, you would have been warned that v[count] was not a pointer.  To
provide the address, you need to use the `&' operator:
    scanf("%d",&v[count]);

Having said all that, the scanf() function is not the preferred way to do
input, since it will not respond well to ill-conditioned input.  Get the FAQ
by anonymous FTP from rtfm.mit.edu, where alternatives are discussed.  You
probably need to learn more C before many things in the FAQ make sense, but it
should still be an early stop (before comp.lang.c) when you have more
questions.

:everything runs correctly, but the nubers i type, won't stay in
:v[count]. it remains zero. why ?
:thanx in advnace
:Mr. Amos Freund

:"200Kph on a big bore UJM. THE fun!"

Honors Bridge Club, 115 E 57th, New York    

 * all newsgroups follow-ups are also emailed */

(comp.lang.c, Tue, 26 Nov 1996 08:14:27 -0600):

:>
:> >
:> > after writing the following lines:
:> > (where v is a one-dimension array, size 7)
:> > printf ("enter the numbers ");
:> > for (count=0;count<=6;count++)
:> >      scanf("%d",v[count]
:> >
:> > everything runs correctly, but the nubers i type, won't stay in
:> > v[count]. it remains zero. why ?
:>
:> You must write:
:>         for ( count = 0 ; count < 7 ; count++ ) // the same that you wrote just more C-like
:>                 scanf ("%d", &v[count]);        // use address of variable
:>
:> C-compiler cannot detect such error, because scanf defined as: int scanf (const char * format, ... );
:> Good luck with C
:> Vladimir
:Oops, my mistake, Vladimir is correct.

SIGH.  Vladimir is right only in inserting the `&' operator.  He is wrong
about changing the for-loop, about needing to insert `// ' syntax errors, and
about what the capabilities of a C compiler are. His net score is clearly
minus.

Honors Bridge Club, 115 E 57th, New York    

 * all newsgroups follow-ups are also emailed */

(comp.lang.c, Tue, 26 Nov 1996 15:17:01 +0200):

:
:You must write:
:       for ( count = 0 ; count < 7 ; count++ ) // the same that you wrote just more C-like
:               scanf ("%d", &v[count]);  // use address of variable

There is no reason to tell him he "must" write
    for(count = 0; count < 7; count++)
instead of
    for(count = 0; count <= 6; count++)
It is in no way more "C-like".

What is NOT "C-like" is telling him that he "must" use syntax errors.  `// '
is not a comment-introduction.  It is an error.  An ANSI-compliant C compiler
will find it so.

:C-compiler cannot detect such error, because scanf defined as: int scanf (const char * format, ... );
:Good luck with C

Get a new C compiler.  Mine has no trouble detecting such an error.  Or the
ones you say we "must" introduce.

:Vladimir

Honors Bridge Club, 115 E 57th, New York    

 * all newsgroups follow-ups are also emailed */

: >Well, i'm a C beginner.
: >i've just switched from pascal.
: >to the point:
: >
: >after writing the following lines:
: >(where v is a one-dimension array, size 7)
: >printf ("enter the numbers ");
: >for (count=0;count<=6;count++)
: >     scanf("%d",v[count]
: >
: >everything runs correctly, but the nubers i type, won't stay in
: >v[count]. it remains zero. why ?

: You need to give scanf() the _address_ of the variable you want it to write to,
: so the scanf() line should be:
:       scanf("%d", &v[count]);
:                  ^^

: Incidently, scanf() is often unpleasant for direct user input - unexpected
: input (letters when it expects a number, for example) can cause problems.  It
: may be better to get a whole line with fgets(), then you can examine it at your
: leisure, scan it with sscanf(), pick it apart with strtok(), etc.  Generally
: much easier to recover from errors this way...

I agree with you a 100%. I just wonder why nobody suggested the simplest
thing if you insis on scanf and that is
    scanf("%d",v + count);
Never mind of course that 'v' as a variable name is plain stupid. What
the heck does it stand for? velocity? vector? venom? victory?

--

If it doesn't work, you're doing it wrong,
If it does, you just got lucky.

However I normaly prefer &v[count] but that is personal taste.

h.f.s.
--
Hans Friedrich Steffani
Institut fuer Elektrische Maschinen und Antriebe, TU Chemnitz-Zwickau

http://www.tu-chemnitz.de/~hfst/

scanf("%d",v[count]

to:

scanf("%d",&v[count])

In otherwords the ampersand, i.e. the & symbol must precede your
variable in the scanf statement. I hope this helps.