C Language, memory Leak: pointer->pointer->pointer->struct

memory Leak: pointer->pointer->pointer->struct

Author	Message
soupbo #1 / 5	memory Leak: pointer->pointer->pointer->struct The following works beautifully if x==y, but if they are inequal, I get a memory leak... the leak seems a very minor one, and doesnt prevent the code from 'working' fine, it just annoys me to have sloppy allocation... was wondering if somebody could tell me how I might avoid it. #include <stdlib.h> typedef struct { int dummy; int dummy2; Quote: } * pt_stupid; int main() { int i,x=500,y=500; pt_stupid bubba; bubba = (pt_stupid ) malloc(y * sizeof(pt_stupid )); for(i=0;i<x;i++) bubba[i] = (pt_stupid ) malloc(x * sizeof(pt_stupid)); return 0; Quote: }
Thu, 25 Mar 2004 00:34:41 GMT

Jarm #2 / 5	memory Leak: pointer->pointer->pointer->struct Quote: > The following works beautifully if x==y, but if they are inequal, I get a > memory leak... the leak seems a very minor one, and doesnt prevent the code > from 'working' fine, it just annoys me to have sloppy allocation... was > wondering if somebody could tell me how I might avoid it. > #include <stdlib.h> > typedef struct { > int dummy; > int dummy2; > } * pt_stupid; > int main() { > int i,x=500,y=500; > pt_stupid bubba; > bubba = (pt_stupid ) malloc(y * sizeof(pt_stupid )); > for(i=0;i<x;i++) > bubba[i] = (pt_stupid ) malloc(x * sizeof(pt_stupid)); > return 0; > } There may also be a leak here as you haven't shown us how you free the allocations but that's not the main problem. The main problem is that there's a bug in your code. Your loop should iterate y times not x times.
Thu, 25 Mar 2004 01:04:02 GMT

soupbo #3 / 5	memory Leak: pointer->pointer->pointer->struct Quote: >> The following works beautifully if x==y, but if they are inequal, I get a >> memory leak... the leak seems a very minor one, and doesnt prevent the > code >> from 'working' fine, it just annoys me to have sloppy allocation... was >> wondering if somebody could tell me how I might avoid it. --snip--- Quote: > There may also be a leak here as you haven't shown us how you free the > allocations but that's not the main problem. The main problem is that > there's a bug in your code. Your loop should iterate y times not x times. DUH!!!!! ... god, I hate it when I look at something for too long and miss the simple things... ... ... thanx 8-)
Thu, 25 Mar 2004 01:07:27 GMT

riha #4 / 5	memory Leak: pointer->pointer->pointer->struct Quote: >The following works beautifully if x==y, but if they are inequal, I get a >memory leak... the leak seems a very minor one, and doesnt prevent the code >from 'working' fine, it just annoys me to have sloppy allocation... was >wondering if somebody could tell me how I might avoid it. >#include <stdlib.h> >typedef struct { > int dummy; > int dummy2; >} * pt_stupid; >int main() { >int i,x=500,y=500; >pt_stupid bubba; >bubba = (pt_stupid ) malloc(y * sizeof(pt_stupid )); >for(i=0;i<x;i++) > bubba[i] = (pt_stupid ) malloc(x * sizeof(pt_stupid)); >return 0; >} Looking at the code as it is, why do you need both x and y? If there's some context, show it! -- rihad
Thu, 25 Mar 2004 13:04:09 GMT

soupbo #5 / 5	memory Leak: pointer->pointer->pointer->struct Quote: >>} > Looking at the code as it is, why do you need both x and y? If there's > some context, show it! Because I included the minimum ammount of compiled code to reflect the specific issues I had. the specific issue I had, dealt with dynamic allocation of a multidimensional array of pointers to structs (pointer->pointer->pointer->struct actualy). It would seem rather silly to dynamicly allocate something without knowing at executiong time what size it needed to be allocated to. x,y Represent those values, but in a more convenient manor for debugging purposes... would you like me to send you the entire project I was working on?? incidentaly, the problem was quite simple, as was pointed out to me earlier (in this group) as I was allocating x x times instead of y times...
Thu, 25 Mar 2004 05:34:28 GMT

Page 1 of 1

[ 5 post ]