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Tom Hosia
#1 / 10
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 converting char to pointer char I wanna call strcat to append a character ch to a string str, but the 2nd
param has to be a pointer so how would I do this if I didn't want to make ch
a character pointer at declaration time
char str[256];
char ch;
/* wanna do this but can't cause ch is not a pointer */
strcat(str, ch);
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| Thu, 29 Apr 2004 11:04:50 GMT |
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Eric Go
#2 / 10
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converting char to pointer char Quote:
> I wanna call strcat to append a character ch to a string str, but the 2nd > param has to be a pointer so how would I do this if I didn't want to make ch > a character pointer at declaration time > char str[256];
> char ch;
> /* wanna do this but can't cause ch is not a pointer */
> strcat(str, ch);
ch isn't a string either, so that will cause you problems as well.
you could try:
char str[256];
char ch[2]; /* you need two elements...one for the character, */
/* and one for the null terminator */
strcat( str, ch );
--
== Eric Gorr =========================================== ICQ:9293199 ===
"Therefore the considerations of the intelligent always include both
benefit and harm." - Sun Tzu
== Insults, like {*filter*}, are the last refuge of the incompetent... ===
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| Thu, 29 Apr 2004 11:33:17 GMT |
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pete
#3 / 10
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converting char to pointer char Quote:
> I wanna call strcat to append a character ch to a string str, but the 2nd
> param has to be a pointer so how would I do this if I didn't want to make ch
> a character pointer at declaration time
> char str[256];
> char ch;
> /* wanna do this but can't cause ch is not a pointer */
> strcat(str, ch);
/* BEGIN new.c */
#include <stdio.h>
#include <string.h>
int main(void)
{
char str[256] = "hello, worl";
char ch = 'd';
size_t length;
length = strlen(str);
str[length++] = ch;
str[length] = '\0';
puts(str);
return 0;
Quote: }
/* END new.c */
--
pete
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| Thu, 29 Apr 2004 11:39:51 GMT |
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Ben Pfaf
#4 / 10
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converting char to pointer char Quote:
> I wanna call strcat to append a character ch to a string str, but the 2nd > param has to be a pointer so how would I do this if I didn't want to make ch > a character pointer at declaration time > char str[256];
> char ch;
> /* wanna do this but can't cause ch is not a pointer */
> strcat(str, ch);
A few approaches:
/* Convert character to string, then concatenate string. */
char str2[2];
str2[0] = ch;
str2[1] = '\0';
strcat (str, str2);
/* Concatenate character to string directly. */
char *p;
p = strchr (str, '\0');
p[0] = ch;
p[1] = '\0';
/* Devious. */
sprintf (strchr (str, '\0'), "%c", ch);
--
"The fact that there is a holy war doesn't mean that one of the sides
doesn't suck - usually both do..."
--Alexander Viro
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| Thu, 29 Apr 2004 11:37:33 GMT |
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Kohn Emil Da
#5 / 10
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converting char to pointer char
Quote:
> > I wanna call strcat to append a character ch to a string str, but the 2nd
> > param has to be a pointer so how would I do this if I didn't want to make ch
> > a character pointer at declaration time
> > charstr[256];
> > char ch;
> > /* wanna do this but can't cause ch is not a pointer */
> > strcat(str, ch);
> A few approaches:
<snipped>
And yet another one:
strncat(str,&ch,1);
Emil
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| Thu, 29 Apr 2004 13:23:05 GMT |
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-hs-
#6 / 10
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converting char to pointer char
Quote: >> > I wanna call strcat to append a character ch to a string str, but >> > the 2nd param has to be a pointer so how would I do this if I didn't >> > want to make ch a character pointer at declaration time >> > charstr[256];
>> > char ch;
> strncat(str,&ch,1);
--
-hs- emdel at noos.fr "support Afghans against Taleban"
"Car les bandits qui sont cause des guerres
N'en meurent jamais, on n'tue qu'les innocents."
Gaston Monthus -- La Butte Rouge
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| Thu, 29 Apr 2004 17:37:28 GMT |
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Serve La
#7 / 10
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converting char to pointer char
Quote: > I wanna call strcat to append a character ch to a string str, but the 2nd > param has to be a pointer so how would I do this if I didn't want to make ch > a character pointer at declaration time > char str[256];
> char ch;
> /* wanna do this but can't cause ch is not a pointer */
> strcat(str, ch);
buf[len] = ch;
buf[++len] = '\0';
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| Thu, 29 Apr 2004 20:11:05 GMT |
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Tom Hosia
#8 / 10
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converting char to pointer char Thanks, I like this solution the best...short and quick!!!
Tom
Quote:
> > > I wanna call strcat to append a character ch to a string str, but the
2nd
> > > param has to be a pointer so how would I do this if I didn't want to
make ch
> > > a character pointer at declaration time
> > > charstr[256];
> > > char ch;
> > > /* wanna do this but can't cause ch is not a pointer */
> > > strcat(str, ch);
> > A few approaches:
> <snipped>
> And yet another one:
> strncat(str,&ch,1);
> Emil
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| Thu, 29 Apr 2004 22:13:50 GMT |
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Jack Klei
#9 / 10
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converting char to pointer char
in comp.lang.c:
Quote:
> > I wanna call strcat to append a character ch to a string str, but the 2nd
> > param has to be a pointer so how would I do this if I didn't want to make ch
> > a character pointer at declaration time
> > char str[256];
> > char ch;
> > /* wanna do this but can't cause ch is not a pointer */
> > strcat(str, ch);
> A few approaches:
> /* Convert character to string, then concatenate string. */
> char str2[2];
> str2[0] = ch;
> str2[1] = '\0';
> strcat (str, str2);
> /* Concatenate character to string directly. */
> char *p;
> p = strchr (str, '\0');
> p[0] = ch;
> p[1] = '\0';
> /* Devious. */
> sprintf (strchr (str, '\0'), "%c", ch);
Not only devious, but undefined.
--
Jack Klein
Home: http://JK-Technology.Com
FAQs for
comp.lang.c http://www.eskimo.com/~scs/C-faq/top.html
comp.lang.c++ http://www.parashift.com/c++-faq-lite/
alt.comp.lang.learn.c-c++ ftp://snurse-l.org/pub/acllc-c++/faq
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| Fri, 30 Apr 2004 05:05:38 GMT |
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Ben Pfaf
#10 / 10
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converting char to pointer char Quote:
> in comp.lang.c:
> > > I wanna call strcat to append a character ch to a string str, but the 2nd
> > > param has to be a pointer so how would I do this if I didn't want to make ch
> > > a character pointer at declaration time
> > > char str[256];
> > > char ch;
> > > /* wanna do this but can't cause ch is not a pointer */
> > > strcat(str, ch);
> > /* Devious. */
> > sprintf (strchr (str, '\0'), "%c", ch);
> Not only devious, but undefined.
Why? There is no overlapping copy, if that's what you're
concerned about.
--
"It wouldn't be a new C standard if it didn't give a
new meaning to the word `static'."
--Peter Seebach on C99
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| Fri, 30 Apr 2004 05:10:30 GMT |
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