Hi,
   As the title says, how can you initialise structure within another
structure without defining the size of the second structure (inner)?

   For example, consider the following code:

/* Example Of Initialising Structure Inside Structure */
#include <stdio.h>

struct Location {
   struct Position {
        int     X;
        int     Y;
   } Point[2];  /* If you don't define the size, you'll get an error */
   int Z;

void main()
{
   Pos.Z = Pos.Point[0].X + Pos.Point[0].Y;
   printf("\nZ = %d\n", Pos.Z);
   Pos.Z = Pos.Point[1].X + Pos.Point[1].Y;
   printf("Z = %d\n", Pos.Z);

        Error...: Size of the type is unknown or zero

Do you know what's wrong with my code and how can I get around this
problem please?

Your help appreciated, and thanx in advance...

     __  _________________________________
    /  ||           Hashem Al-Dhaheri

  /____||      ____     ___     ___ ___
 /     ||  -  /   //__//__//__//__ /___) /
/      ||___ /___//  //  //  //__ /   \ /

: struct Location {
:    struct Position {
:         int     X;
:         int     Y;
:    } Point[2];  /* If you don't define the size, you'll get an error */
:    int Z;
: };

This restriction is inherent to the language: given a structure's
declaration its layout is constant. To allow variable sized array,
use a pointer:
        struct Location{
                struct Position *Point;
                int Z;
        };
and then allocate the point field separately:
        struct Location zoe;
        zoe.Point = malloc(jamie*sizeof(struct Point));
        zoe.Z = victoria;

There are other ways, but this should work for now.
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        struct Position {
                int     X;
                int     Y;
        };

        struct Location {
                                Location() Z(0), point(0) {};
                struct Position *point;
                int             z;
        } location;

        location.point = new Position[2];

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Wade Guthrie                     |

I don't speak for Rockwell.      |  Sucks Syntax.