But I just can't figure it out now.  Ok, here it goes.  I was making a C
program that changed fractions to decimals.  But, everytime I try to do
It, I come up with 0.  If I change it from / to +, it adds fine.  Well,
here is a simplied  copy of the code.  PLEASE HELP! (I most likely just
need to change the data type..........)

#include <stdio.h>
long input;
long answer;
long inp;
main()
 {
  printf("Enter a number:  ");
  scanf("%d", &input);
  printf("Enter another number:  ");
  scanf("%d", &inp);
  answer = input / inp;  //Right here.  If I change it to add or
subtract, it will work fine.
  printf("The answer is %d", answer);
  return 0;
 }

   But I just can't figure it out now.  Ok, here it goes.  I was making a C
   program that changed fractions to decimals.  But, everytime I try to do
   It, I come up with 0.  If I change it from / to +, it adds fine.  Well,
   here is a simplied  copy of the code.  PLEASE HELP! (I most likely just
   need to change the data type..........)

Yes.  Change your data type to `double' for double-precision floating
point arithmetic, and your scanf()'s to %f.  BTW, scanf() isn't
usually a good function to use.

Change answer, or all of them if you wish, to type float.

You inadvertently left the 'l' out of your format specifier.  A new person
might get confused.  For the new person, this is from the C-FAQ:

12.13:  Why doesn't this code:

                double d;
                scanf("%f", &d);

        work?

A:      Unlike printf(), scanf() uses %lf for values of type double, and
        %f for float.  See also question 12.9.
--
Hypertext C-FAQ: http://www.eskimo.com/~scs/C-faq/top.html
C-FAQ ftp: ftp://rtfm.mit.edu, C-FAQ Book: ISBN 0-201-84519-9
Try "C Programming: A Modern Approach" ISBN 0-393-96945-2
Want Software?  Algorithms?  Pubs? http://www.infoseek.com

-- glen

:But I just can't figure it out now.  Ok, here it goes.  I was making a C
:program that changed fractions to decimals.  But, everytime I try to do
:It, I come up with 0.  If I change it from / to +, it adds fine.  Well,
:here is a simplied  copy of the code.  PLEASE HELP! (I most likely just
:need to change the data type..........)
================
Since you haven't gotten the C-FAQ from
ftp://rtfm.mit.edu/pub/usenet-by-group,
you have left yourself open to flammage.  The use of the evil scanf function,
the (not-yet-allowed) '//' syntax error for comments, and the
(soon-to-be-deprecated)
implicit declaration of main mark you as a newbie, ripe for the
crackle-crackle.
But when you do get the FAQ, you will find this:
3.14: Why doesn't the code

  int a = 1000, b = 1000;
  long int c = a * b;

 work?

A: Under C's integral promotion rules, the multiplication is
 carried out using int arithmetic, and the result may overflow or
 be truncated before being promoted and assigned to the long int
 left-hand side.  Use an explicit cast to force long arithmetic:

  long int c = (long int)a * b;

 Note that (long int)(a * b) would *not* have the desired effect.

 A similar problem can arise when two integers are divided, with
 the result assigned to a floating-point variable.

 References: K&R1 Sec. 2.7 p. 41; K&R2 Sec. 2.7 p. 44; ANSI
 Sec. 3.2.1.5; ISO Sec. 6.2.1.5; H&S Sec. 6.3.4 p. 176; CT&P
 Sec. 3.9 pp. 49-50.

================
:
:
:#include <stdio.h>
:long input;
:long answer;
:long inp;
:main()
: {
:  printf("Enter a number:  ");
:  scanf("%d", &input);
:  printf("Enter another number:  ");
:  scanf("%d", &inp);
:  answer = input / inp;  //Right here.  If I change it to add or
:subtract, it will work fine.
:  printf("The answer is %d", answer);
:  return 0;
: }
:

Be aware that answer is a long integer, though, so it will convert that
result back into an integer, which is basically what happens with
integer division.  You should make it a float or double and printf it
with the %f conversion specifier.

--

I believe we can change anything.
I believe in my dream.
    - Joe Satriani

--

I believe we can change anything.
I believe in my dream.
    - Joe Satriani