What I have looks like this:

void function(char* variable)
{
  const char* var = variable;
  function_that_needs_const_char(var);
  return;

Is this:
a.) correct?
b.) the best way to do this?

Thanks for help!

rt

a.) yes
b.) no.  YOu don't need var; you can just code

        function_that_needs_const_char(variable);

--
Michael M Rubenstein

Yes, conversion from a pointer to a type to a to a pointer to a
more qualified version of that type is "safe" and supported in C
as an explicit conversion. Essentially a pointer to a const type
indicates that you won't modify what the pointer points to using that
pointer or a pointer derived from it.

Since it is supported implicitly there is no need to use an extra
varaible just for the conversion:

void function(char* variable)
{
  function_that_needs_const_char(variable);
  return;

You probably use this sort of thing all of the time without thinking
about it e.g.

   printf("Some text\n");

A string literal has type array of char which gets converted to a
pointer to its first element (i.e. a char *) in a value context like this.
printf() requires a const char * as its first argument and the compiler
performs the conversion automatically. Other standard library functions
like strcmp(), fopen() also take const char * arguments and are happy
to take char *.

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