main()
{
    char direction[15];

    printf("What direction do you want to go?-->");
    scanf(" %s", direction);

    if (direction == 'n')
       {
         printf("You went North.");
       }

    return 0;

Gergo

--
I think that all good, right thinking people in this country are sick
and tired of being told that all good, right thinking people in this
country are fed up with being told that all good, right thinking people
in this country are fed up with being sick and tired.  I'm certainly
not, and I'm sick and tired of being told that I am.
                -- Monty python

GU d- s:+ a--- C++>$ UL+++ P>++ L+++ E>++ W+ N++ o? K- w--- !O !M !V
PS+ PE+ Y+ PGP+ t* 5+ X- R>+ tv++ b+>+++ DI+ D+ G>++ e* h! !r !y+

Greg Martin

Yes.

 : You either want "n" or use getchar() to take input.

No. You can't do
  if (direction == "n")
which seems to be what you are suggesting (use strcmp() in this case).

Perhaps OP should try
  if (direction[0] == 'n' || direction[0] == 'N')
So if I enter "North", it will still work as intended.

 :>    char direction[15];
 :>    if (direction == 'n')

--
John Rixon

No, arrays are not first class objects in C.  Given the definition
from the original post:

char direction[15];

the conditional test:

if (direction == "n")

will always be false because the array references decay into pointers,
so the actual comparison is:

if (&direction[0] == &"n"[0])

that is, compare the address of the first character in the array
direction with the address of the first character in the unnamed array
containing the string literal.

These two addresses will never be the same.

</Jack>
--
Do not email me with questions about programming.
Post them to the appropriate newsgroup.
Followups to my posts are welcome.

James a crit:

Here is another (maybe better) way to do this...

int main()
{
    char direction;

    printf("What direction do you want to go? (N/S/W/E) ");
    direction = getchar ();

    switch (direction)
    {
        case 'n':
        case 'N':
            printf ("You went North");
            break;
        case 's':
        case 'S':
            printf ("You went South\n");
            break;
        case 'w':
        case 'W':
            printf ("You went West\n");
            break;
        case 'e':
        case 'E':
            printf ("You went East\n");
            break;
        default:
            printf ("You went no where\n");
    }

    return 0;

Tom

     return 0;
 }

Direction is a pointer to character,if ypu want to know what it shows,you
must use dereferencing operator *
The correct if statement is:
  in C
    array[i] = *(array + i)
  so array[0] =*array

   if(*direction == 'n')

if user inputs a string contains more than one character,for example
  "North"
*direction='N'
*(direction + 1) ='o'
*(direction + 2) ='r'
  .
  .
  .
  .
i suggest you take a look array pointer relationship..

...

     fflush(stdout);

here otherwise the prompt may not be displayed before the program pauses for
input.

...

In fact you have HTML encoding turned on which causes all of this rubbish
to be included. Please turn it off ASAP.

--
-----------------------------------------


-----------------------------------------

p.s. putting that space you have in scanf doesn't do what I think you think
it does.

from documentation on scanf format strings:
The format string contains regular characters which must match the input
exactly as well as a conversion specifiers, which begin with a percent
symbol.  Any whitespace in the format string matches zero or more of any
whitespace characters in the input.  Thus, a single space may match a
newline and two tabs in the input.  All conversions except `c' and `[' also
skip leading whitespace automatically.

...In other words, if you want to print a space, you have to do it in
printf(). If you want scanf to skip leading whitespace, don't worry it will
already do it.