Hi Netters

I have a really simple question.

       1: #include <stdio.h>
       2:
       3: main()
       4: {
       5:         void (*ptr)();
       6:         void test();
       7:
 >     8:         ptr = test;
       9:         ptr();
      10:         (*ptr)();
      11:
      12: }
      13:
      14: void test()
      15: {
      16:         printf(" this is a test\n");
      17: }
      18:

both calls on line 9 and 10 work, but I am not quite sure I understand
why the call ptr() works. (correct way to call is on line 10). Can
someone be kind as to shed light on the subject ????

Thanks

Madhavi

--
If the Earth is the size of a pea in New York, then the Sun is a beachball 50m
away, Pluto is 2km away, and the next nearest star is in Tokyo.  Now shrink
Pluto's orbit into a coffee cup; then our Milky Way Galaxy fills North America.

typedef void Func_t(void);

Func_t test;     /* forward decleration of test */

  Func_t *Func;  /* decleration of pointer to a function of type:- void name(void) */
  Func = test;

  Func();        /* calls the function test */

You can say Func = &test; for the assignement and you can say (*Func)() to call the
function. But then the syntax looks mighty awfull.

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