How to do int func(int size,int matrix[][size])
Quote:
>>int generate_determinant(int size, int matrix[][size])
>>{ ... }
>>Is this possible?
>mightn't it be just as easy to do
>int generate_determinant( int rows, int columns, int *matrix)
I would tend to solve this as outlined below, given my object-oriented
bent...
typedef struct {
int rows, cols;
int *mat;
Quote:
} matrix_t;
...
matrix_t *create_matrix(int rows, int cols)
{
matrix_t *new_mat = malloc(sizeof(matrix_t));
if (new_mat) {
new_mat->mat = malloc(rows * cols * sizeof(int));
if (new_mat->mat) {
new_mat->rows = rows;
new_mat->cols = cols;
}
else {
free(new_mat);
new_mat = NULL;
}
}
return new_mat;
Quote:
}
void destroy_matrix(matrix_t *matrix)
{
free(matrix->mat);
free(matrix);
Quote:
}
int *matrix_ref(matrix_t *matrix, int row, int col)
{
return matrix->mat + row * matrix->cols + col;
Quote:
}
---------------
Given these definitions, a routine passed a matrix_t automatically knows
its dimensions, and the matrix_ref interface means you don't need to roll
your own address calculations. A typical use might look like:
...
matrix_t *my_matrix;
my_matrix = create_matrix(5, 10);
*matrix_ref(my_matrix, 3, 4) = 12;
and so forth. I have left out some obvious error checking, but I'm sure
you get the idea. I hope this helps!
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