Getting date and time from two 32 bit numbers

Quote:

> Hi,

> I have a problem of handling 64 bit quantity. Can anyone provide me

> any inputs (or solution)??? I explain the problem below:

> I have two 32-bit numbers(Stored 64 bit quantity as two 32 bit

> quantities.- one being high 32 bit and the other low 32 bit). This

> whole 64 bit number gives number of milliseconds past 1st January

> 1600. I have to arrive at date and time.(in other words, I have to

> convert this number of milliseconds to 'a' years, 'b' months, 'c'

> days, 'd' hours, 'e' minutes, 'f' seconds and

> 'g' milliseconds.). This involves division of two 32 bit

> number by a 32 bit number and storing the result in a 32 bit

> number. Hope problem is clear. Can anyone help me???

> thanks,

> Kishore.

Your best bet is to get a large number library and just copy the num

into that, otherwise you could easily code some routines yourself.

Naively you could repeatedly subtract 31,536,000,000 until you get a

result <= it, that is the number of years, then just subtract 86,400,000

until you get a no.....

Subtraction is rather simple, if (a, b) is your input (high, low) and

you are subtracting (c, d) then you get

b1 -= d;

a -= (c + (b1 > b));

b = b1;

Tom

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