/ /***   VERSION 2 ***/
/
/ funptr.c :
/
/ #include <stdio.h>
/ #include "funptr2.h"
/
/ void name(char *nom){
/     printf("NAME:: %s\n",nom);
/ }

type is sort of (void ()(char*))

/ void age(int years){
/    printf("AGE :: %d\n",years);
/ }

type is sort of (void ()(int))

/
/ void gender(char mf, char *sex){
/    if (mf == 'm')
/       printf("Male :: %s\n",sex);
/    else
/       printf("Female :: %s\n",sex);
/ }

type is sort of (void ()(char,char*))

/ int main(void){
/    void *((*p)());                        /* pointer to a function pointer
/ */
/    void *((*p2)()) = NULL;
/    void *((*p3)());

No, these are pointers to a function (with unknown arguments) which
returns a void*.

/
/    p = (void *) name;
/    p ("Hello there");

Casting name to (void*) turns off pointer type checking, presumably
necessary because you're using the wrong type. To make the assignment
without a cast,

    void (*p)(char*);

/    p = (void *) age;
/    p (25);
/
/    p = (void *) gender;
/    p('M',"Male");
/
/    p2 = p('F',"Hello");
/
/    p2;

Loads and then discards the value of p2. To force a call you must include
an argument list even if it's empty.

/    p3 = p2;
/
/    name2();    
/ }
/
/ funptr2.c:
/ #include <stdio.h>
/
/    extern void *((*p3)());
/
/ void name2(void){
/
/    printf("Before Function\n");
/    p3;                          /* This does nothing */

Loads and then discards the value of p3. To force a call you must include
an argument list even if it's empty.

/    printf("After Function\n");
/
/ }
/
/ funptr2.h:
/ void name2(void);

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