I was wondering if there's a function in C that given an integer between 0
and 127, returns the char with the index in ASCII table that corresponds to
the integer given.  I want the OPPOSITE of:

---------- below is the opposite of what i want---------------

char my_char = 'a';
int ascii_idx;

ascii_idx = (int)my_char;

----------

----- below is what i want ------------

As an example, I would like:

f(65) = 'A'
f(97) = 'a'

etc...

Thanks very much for any help

int index = 65;
char character = index;

?

dave

If you need this to work on non-ASCII systems, you can create a lookup
table with the local equivalent of each ASCII character indexed by the
ASCII value of that character, so that, for example,
ASCII_table[65]=='A'
(which would be, for example, 193 (if I'm reading the table correctly)
on an EBCDIC system).  The nice thing about this is that you can portably
initialize this by using character constants:
--------
char ASCII_table[]={-1,-1,/*-1s for ASCII characters with no equivalent in
                             the basic execution character set*/,
                        'A','B','C',/*...*/,
                        'a','b','c',/*...*/};
--------
(you can read the characters off of an ASCII table when you code the
initialization of the lookup table).

dave

char f(unsigned int x) { return x; }