C Language, question about array?

question about array?

Author	Message
Cody Caughla #1 / 5	question about array? Quote: > I need assign values from arr1to another array arr2 -> > arr2[24]={0,1,2,3,4,5,............24} accordingly > like int arr2[0]=arr1[0]; What you want is to loop through each element of the array and assign each value the same in each array. For example - in your array of 24 elements: for(k = 0;. k < 24; k++) arr1[k] = arr2[k]; Would work. Where k is a counter variable acting as the index, after each repetition of the loop, k is incremented by one, thus cycling through all the elements of the array. /Cody
Thu, 27 Sep 2001 03:00:00 GMT

Lmve #2 / 5	question about array? I'm very new to C programm. If someone knows: I have int arr1[2]={01}; but tnis numbers dinamically changes like 02,03... until it's get 24 like 24 hours a day. I need assign values from arr1to another array arr2 -> arr2[24]={0,1,2,3,4,5,............24} accordingly like int arr2[0]=arr1[0]; How to do this?
Fri, 28 Sep 2001 03:00:00 GMT

Stephan Wilm #3 / 5	question about array? Cody Caughlan schrieb: Quote: > > I need assign values from arr1to another array arr2 -> > > arr2[24]={0,1,2,3,4,5,............24} accordingly Be careful, because this is not exactly correct. For an array of size 24 you need 24 initialisers, not 25 as you indicate. IOW use 0 to 23. Quote: > > like int arr2[0]=arr1[0]; > What you want is to loop through each element of the array and assign each value > the same in each array. For example - in your array of 24 elements: > for(k = 0;. k < 24; k++) > arr1[k] = arr2[k]; The concept is sound, but two little bugs managed to sneak in: - there is a '.' after the first ';' in the "for" - you got "arr1" and "arr2" the wrong way round in the assignment Stephan (initiator of the campaign against grumpiness in c.l.c) (-: A brandnew excellent FAQ version has been released !!! :-) (-: Get it: http://www.eskimo.com/~scs/C-faq/versions.html :-)
Fri, 28 Sep 2001 03:00:00 GMT

Arkady Palary #4 / 5	question about array? Quote: > > I need assign values from arr1to another array arr2 -> > > arr2[24]={0,1,2,3,4,5,............24} accordingly > > like int arr2[0]=arr1[0]; > What you want is to loop through each element of the array and assign each value > the same in each array. For example - in your array of 24 elements: > for(k = 0;. k < 24; k++) > arr1[k] = arr2[k]; > Would work. Where k is a counter variable acting as the index, after each > repetition of the loop, k is incremented by one, thus cycling through all the > elements of the array. > /Cody It is possible, to use memcpy() too. For example, int arr_dst[ SIZE ]; int arr_src[ SIZE ]; memcpy( (void )arr_dest, (void )arr_src, sizeof( int )*SIZE );
Fri, 28 Sep 2001 03:00:00 GMT

Lawrence Kir #5 / 5	question about array? Quote: >It is possible, to use memcpy() too. For example, >int arr_dst[ SIZE ]; >int arr_src[ SIZE ]; >memcpy( (void )arr_dest, (void )arr_src, sizeof( int )*SIZE ); Or more simply (and clearly): memcpy(arr_dest, arr_src, sizeof arr_dest); -- ----------------------------------------- -----------------------------------------
Fri, 28 Sep 2001 03:00:00 GMT

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