dylan, Naive Number Question

Naive Number Question

Author	Message
Rob Myer #1 / 2	Naive Number Question Thank you very much. :-) - Rob. Quote: > > Hi. > > How can I round a number (a <float>) to the nearest n decimal places in > > (Gwydion) Dylan? > round/(number, expt(10, - n)) / expt(10, n) > [probably don't have the syntax right, but you get the idea] > Or write your self a scaled/decimal number type ;-).
Fri, 30 May 2003 04:06:08 GMT

Pichai Asoka #2 / 2	Naive Number Question Quote: > Hi. > How can I round a number (a <float>) to the nearest n decimal places in (Gwydion) Dylan? > Thanks. > - Rob. This is the fortran stuff I used to do :-) I am sure you can find the dylan equivalent rounded = int(unrounded * 10^n + 0.5) /10^n where int is a function that truncates a float and returns the integer part. Of course some addl scaffolding is reqd to handle neagtive numbers etc HTH P Asokan
Fri, 30 May 2003 10:12:08 GMT

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