HI,
I need to solve a second degree equation in Visual Basic....something
like this:
12.32*X^2 + 179.24*X - 958.1625 = 0
and I need the "positive" ( X=4.157 ) solution to be defined in a
variable
Im using Visual Basic 4.
Can anybody help me??

 Thanks in advance

Joao Marques

Hello !

Eq :
        aX2+bX+c=0
calculate :
        d=b2-4*a*c
if d<0, there is no real solution.
if d=0, there is only one solution :
        X= -b/(2*a)
if d>0, ther is two real solutions
        X1= (-b+sqrt(d))/(2*a)  (sqrt = square root)
        X2= (-b-sqrt(d))/(2*a)
Then, you just have to choose the one you want.

bye.
                        Sylvain.