How can I split an integer into 2 addresses (high and low bytes)

I have the code of how to do it in C, but I'm having trouble converting it
to VB :

(Base is an int)

    WBlock[0] = ( Base >> 8 ) & 0xFF ;
    WBlock[1] = Base & 0xFF ;

Could you possibly mail me due to problems with reading news.

Thanks in advance

Rich

FUNCTION HByte% (word%)
IF word% >= 0 THEN
                HByte% = word% \ 256
        ELSE
                HByte% = (65536 + word%) \ 256
        END IF
END FUNCTION

FUNCTION LByte% (word%)
IF word% >= 0 THEN
                LByte% = word% MOD 256
        ELSE
                LByte% = (65536 + word%) MOD 256
        END IF
END FUNCTION

Of course, if you know that you'll only be dealing with positive integers
less than 32767 (like a positive signed int in C) just use MOD or '\'
(integer divide). So in order to get the lowbyte value of 23456 just say

PRINT lbyte(23456)

or

PRINT 23456 MOD 256

Byte0 = Word AND &HFF
Byte1 = (Word AND &HFF00) \ &H100

...or

Byte0 = ASC(MID$(MKI$(Word), 1, 1))
Byte1 = ASC(MID$(MKI$(Word), 2, 1))

Beau Schwabe

Lotsa different technques I see! here;s my two cents on how I do it:

Number = 32767
MSB = Number \ 256      'backslash = integer div
LSB = Number MOD 256

Works for me! Ep

Ed Parry - Southern California, USA

: How can I split an integer into 2 addresses (high and low bytes)
:
: I have the code of how to do it in C, but I'm having trouble converting it
: to VB :
:
: (Base is an int)
:
:     WBlock[0] = ( Base >> 8 ) & 0xFF ;
:     WBlock[1] = Base & 0xFF ;
:
: Could you possibly mail me due to problems with reading news.
:
: Thanks in advance
:
: Rich

:

RI>I have the code of how to do it in C, but I'm having trouble converting it
RI>to VB :

I don't know VB but:

low = Value AND 255
high = (value AND -256)/256