Could anyone help me with the following:

I have a decimal number  nnnnnnnn in variable Var1
I need to convert this to it's binary equivalent store it in a variable
Var2.
Take Var2 and AND (binary AND) with another binary number 0000000 and
store the result in Var3.

An equivalently good one would be to replace the last x number of digits
in the binary variable Var2 with 0s.
I need to do this within awk.

Thank you

Could anyone help me with the following:

I have a decimal number  nnnnnnnn in variable Var1
I need to convert this to it's binary equivalent store it in a variable
Var2.
Take Var2 and AND (binary AND) with another binary number 0000000 and
store the result in Var3.

An equivalently good one would be to replace the last x number of digits
in the binary variable Var2 with 0s.
I need to do this within awk.

Thank you

gawk 3.1 has binary bit operators.

Before that, I did something like this:

function and(a, b    , res, p2, abit, bbit)
{
        res = 0; # the result
        p2 = 1; # power of 2 - the bit
        while ( (a > 0) || (b > 0) )
        {
                abit = a % 2;
                bbit = b % 2;
                a = (a-abit)/2
                b = (b-bbit)/2
                if ( abit && bbit )
                {
                        res = res + p2
                }
                p2 += p2
        }
        return res

Grungy and slow, but (unless typos here) it worked.

Martin Cohen